[Histonet] RE: equation problem PLEASE help

[JR R]

Hi Eva.  Here’s how I
would do it.

 

(1 mole/1064 grams)*(.001 gram/ml)= 9.4 X 10^-7 mole/ml

 

Concentration 1*Volume 1= Concentration 2 * Volume 2, or
C1V1=C2V2

 

C1= 9.4 X 10^-7 mole/ml

 

C2= 10X 10^-9 mole/ml

V2= 2 ml

 

Solving for V1...

 

V1= (C2V2)/C1

 

V1= (10 X 10^-9 mole/ml*2.0 ml)/ 9.4 X 10^-7 mole/ml=.021 ml

 

You need about 21 microliters of stock solution to make 2
mls of working solution.

 

Use a calculator or Excel to get as many decimal places as
you need.

 

Jerry Ricks

Research Scientist

University of Washington

Department of Pathology






> From: eca9 <@t> georgetown.edu
> To: histonet <@t> lists.utsouthwestern.edu
> Date: Wed, 7 Jan 2009 16:46:23 -0500
> Subject: [Histonet] equation problem PLEASE help
> 
> Good afternoon,
> I am hoping someone out there will take pity on a "mathematically" challenged individual such as myself. I have been trying for hours to wrap my head around this equation and am now getting to the point where I am more confused than ever. Please help me.
> The protocol calls for 10nmol of a substance per 1ml needed. It comes in a 1mg/ml solution and has a molecular weight of 1064g/mol. How do I do this? If for example I needed 2ml of the solution...
> The clearer the explanation the better. I really want to understand the calculation not just have an answer. PLEASE HELP ME.
> Thank you,
> Eva
> 
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