[Histonet] Gravimetric Factor Equation
Connie McManus
convmcm <@t> cc.usu.edu
Tue Jun 15 11:17:11 CDT 2004
I have never bothered with gravimetry calculations, but it's always good
to know for times when you do notice a difference in the quality of
staining. In my lab, a notebook is kept on everything we use ...
antibodies, stains, etc. Things found on the bottle and or the data
sheet are entered into this log book along with the date received,
opened, etc. So if ever we do encounter a problem with new dyes,
antibodies, whatever, we have a quick and easy reference. The original
data sheets are also kept, but I find a log book easier to deal with.
Connie McManus
Utah Veterinary Diagnostics Laboratory
Utah State University
Logan, UT
Phone: 435/797-1891
fax: 435/797-2805
-----Original Message-----
From: histonet-bounces <@t> lists.utsouthwestern.edu
[mailto:histonet-bounces <@t> lists.utsouthwestern.edu] On Behalf Of
lpwenk <@t> sbcglobal.net
Sent: Tuesday, June 15, 2004 2:59 AM
To: Dave; histonet <@t> lists.utsouthwestern.edu
Subject: Re: [Histonet] Gravimetric Factor Equation
Gravimeter factor =
(conc of present dye)
__________________ X (grams of old dye used.)
(concentration of new dye)
Let's say your present dye is 75% dye (meaning 25% salts, fillers,
impurities - things that won't color the dye, but are a by-product or
possible needed to make the correct charge). And the solution you have
been
making are working great. Now you buy a new bottle of the same dye. It's
dye
concentration is 50% (meaning 50% salts, fillers, impurities, etc.).
Obviously, the new dye is much weaker, so in order for the new dye to
stain
as darkly as the old dye, hopefully it would make sense that MORE of the
new
dye is needed.
If the solution you are to make is a 2% solution, that's 2 grams in 100
mL
of solvent (water, alcohol). (If the math doesn't show up right, make
the
screen of your email full size)
(75%)
_____ X (2 g) = (150) / (50) = 3 grams of new weaker dye are
needed
(50%)
Conversely, if the old dye was 75%, and the new dye is 95%, then the new
dye
is more concentrated. So for the new stronger dye to stain as pale as
the
old dye, less of the new dye must be used.
(75%)
_____ X (2 g) = (150) / (95) = 1.58 grams of the new stronger dye
needed
(95%)
(Percent signs cancel themselves out, leaving the grams.)
Just to let you know, in our lab, we usually don't pay attention to GF.
First of all, many of our dyes seem fairly consistent in percentage from
one
lot to another (87% vs 85% for example), so there isn't that big of a
change
in amount needed. Second, for example, if we are make up a 1% light
green
counterstain, we end up re-using it for 3-4 months. Therefore, by the
end of
4 months, it's no longer 1%, it is a much lower percent/much weaker
solution. What used to take 1-2 seconds to stain when it was freshly
made
up, now takes 30 seconds. As histotechs, we "eyeball" the quality of the
stained control (with or without the microscope), and adjust time
accordingly. And our procedures reflect that (stain in light green 2-30
seconds until background is pale).
But, yes, sometimes this can cause a problem (when the lot percentages
vary
considerably) and adjustments are made. Someone puts a sign on the dye
bottle that says "Use 1.2 grams for every 1.0 grams needed", for
example.
Hope this helps.
Peggy A. Wenk, HTL(ASCP)SLS
William Beaumont Hospital
Royal Oak, MI
----- Original Message -----
From: "Dave" <tynchas <@t> aol.com>
To: <histonet <@t> lists.utsouthwestern.edu>
Sent: Monday, June 14, 2004 12:11 PM
Subject: [Histonet] Gravimetric Factor Equation
Hello
In Freida Carson's book on histology, she has written to find the
gravimetric factor of a dye is conc of present dye
conc of new dye
However study questions that I've been reviewing have the formula
inverted.
I'm sure that Freida Carson is correct but I need to know for sure. I
haven't had any luck on the internet and co workers don't have a clue
about
what I'm talking about. Thanks in advance.
Dave
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